A soild cube is cut into eight cubes of equal volumes.find the ratio of the total surface area of the given cube and that of one smaller cube
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Let the side of original cube(larger cube) be A units.
And let the side of new cube(small cube) be a units.
Now, volume of larger cube = 8 × volume of one small cube
A³ = 8 × a³
⇒ A = 2a (By taking cube root both sides)
Now, Total surface area of cube = 6 × Side²
⇒ Ratio of total surface area of given cube to that of small cube will be :
6 × A² : 6 × a²
⇒ 6 × (2a)² : 6 × a² (Putting A = 2a)
⇒ (2a)² : a²
⇒ 4a² : a²
⇒ 4 : 1
∴Ratio of total surface area of the given cube to that of one smaller cube = 4:1.
And let the side of new cube(small cube) be a units.
Now, volume of larger cube = 8 × volume of one small cube
A³ = 8 × a³
⇒ A = 2a (By taking cube root both sides)
Now, Total surface area of cube = 6 × Side²
⇒ Ratio of total surface area of given cube to that of small cube will be :
6 × A² : 6 × a²
⇒ 6 × (2a)² : 6 × a² (Putting A = 2a)
⇒ (2a)² : a²
⇒ 4a² : a²
⇒ 4 : 1
∴Ratio of total surface area of the given cube to that of one smaller cube = 4:1.
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