Math, asked by devjanvi, 1 year ago

A sold a table to B at a profit of 15 percent; later on B sold it back to A at a profit of 20 percent thereby gaining ₹ 69 . How much did he A pay for it ?

Answers

Answered by MakutoShiedo
3
Let the CP for A be ₹x.

Profit % = 15%

SP for A = (1 + 15/100) × CP

= 115/100 × ₹x

= ₹23x /20

SP for A = CP for B

Therefore, CP for B = ₹23x/20

Profit% = 20%

SP for B = ( 1 + 20/100) × CP

= 120/100 × ₹x

= ₹6x/5

Profit for B = SP - CP

= ₹6x/5 - ₹23x/20

= ₹x/20

Acc. to the question -

=> ₹x/20 = ₹69

=> ₹x = ₹69 * 20

=> ₹x = ₹1380

Money paid by A to B = ₹6x/5

= ₹ 6 × 1380 /5

= ₹1656

Ans.= A paid ₹1656 for it.

Hope it helps!!!

devjanvi: Sry this ans is wrong
MakutoShiedo: The last sentence of ur q is ---> how much did he A pay for it
MakutoShiedo: he n A?????
MakutoShiedo: correct that error....n Accordingly i solved
devjanvi: Ohk
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