A soldier fires a bullet horizontally from a top of a cliff from a velocity of 10m/s. If the bullet strikes the ground after 2 second. find the height of the cliff. Also calculate the velocity with which the bullet strikes the ground.
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Answer:
Initial and final velocities are same = 10m/s
Time is 2 second
And acceleration is 10 m/s^2
so,
v = g x t = 20 m/s
Final velocity of the bullet as it strikes the ground is given by--
so 10√5 m/s^2 is final velocity
Let h be the height of the cliff.
so, height = 0.5gt^2 = 20 m
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