Question

A solenoid 20 cm long is wound with 500 turns of wire. Find the current required to establish a magnetizing force of 2500 A/m inside the solenoid. (complete sol)

Answer 1

Given that,

Length l= 20 cm

Number of turns N= 500

Magnetizing force H = 2500

We need to calculate the current required to establish a magnetizing force inside the solenoid

Using formula of Magnetizing force

$H=\dfrac{NI}{l}$

$I=\dfrac{Hl}{N}$

Where, H = Magnetizing force

l = length

I = current

N = number of turns

Put the value into the formula

$I=\dfrac{2500\times20\times10^{-2}}{500}$

$I= 1\ A$

Hence, The current required to establish a magnetizing force inside the solenoid is 1 A.