Question

y= log √x-1/✓x+1 find dy/dx​

Answer 1

Answer:

-1/2√x^2-1

Step-by-step explanation:

Given:- y=log{√x-1-√x+1}

To find:- dy/dx

Solution:-

dy/dx=1/√x-1-√x+1[1/2(x-1)^-1/2-1/2(x+1)^-1/2]

dy/dx=1/√x-1-√x+1×1/2[√x+1-√x-1/√x+1(√x-1)]

dy/dx= -1/2√x^2-1

Hope it helps you!

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