A
solenoid has 2.0 x 10³ turns per metre
If we wish to obtain a magnetic field
of 8.0×10^-4 Tesla , what should be the
value of current in solenoida
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Answer:
Magnetic field due to solenoid
B = uNi
Given B = 8.0 × 10^-4
N = 2.0 × 10^3 , u = 2pi × 10 ^-7
By applying them in the formula
8.0 × 10 ^-4 = 2 ×3.14 × 10 ^-7 × 2.0 × 10 ^3 × i
i = 8.0 × 10^-4 / 12.56 × 10 ^-4
i = 8 / 12.56
i = 0.64 amperes
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