Question

A solenoid of length 0.4 m, having 500 turns
and 3A current flows through it. A coil of
radius 0.01 m and have 10 turns and carries
current of 0.4 A has to placed such that its
axis is perpendicular to the axis of solenoid,
then torque on coil will be
(1) 5.92 x 10-6 Nm
(2) 5.92 x 10-5 N.m
(3) 5,92 x 10-4 N.m
(4) 0.592 x 10-3 Nm​

Answer 1

Answer:

Magnetic field due to larges solenoid

B=

l

μ

0

NI

=

0.4

4×10

−7

×500×3

N=500

I=3

l=0.4

Torque M solenoid I× Area of corn section ×B

=0.4×π0.01

2

×4π×

0.4

10

−7

×500×3

orque =π.0.01

2

×4π×10

−7

×500×3

Torque =5.92×10

−7

N−m