A solid ab has cscl type structure number of nearest cations
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In CsCl structure the distance the closest approach between the cation and anion is equal to half of the body of the diagonal of a cube.
Body diagonal =
3
–
√
×
3×
Edge Length
=
3
–
√
×404
=3×404
=699.74pm
=699.74pm
The distance of the closest approach =
1
2
×
12×
Body diagonal
=
1
2
×699.74
=12×699.74
= 349.87 pm = 349.9pm
Body diagonal =
3
–
√
×
3×
Edge Length
=
3
–
√
×404
=3×404
=699.74pm
=699.74pm
The distance of the closest approach =
1
2
×
12×
Body diagonal
=
1
2
×699.74
=12×699.74
= 349.87 pm = 349.9pm
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