Question

A solid block weighing 100 N is lying on a table for which the coefficient of friction between the block and the total surface is 0.30. Determine the force acting at an angle of 40 degree with the horizontal which would move it a. 45.3 N b. 31.2 N c. 20.18 N d. 27.2 N9o​

Answer 1

Answer:

We have formula

F

min

−μN

Here μ= coefficient of function =

3

1

and N=100 N

So F

min

=

3

100

ans