Question

The value of ‘K’ for which the system of equation x+2y-3=0 and 6x+Ky+7=0 has no solution, is
a) 12
b) 15
c) 8
d) 13​

Answer 1

Answer:

ANSWER IS 12

Step-by-step explanation:

NO SOLUTION MEANS LINES ARE PARELLEL THEN A1/A2=B1/B2AND NOT EQUAL TO C1/C2

A1/A2=1/6

B1/B2=2/K

2/K=1/6 CROSS MULTIPLICATION

2 MULTIPLIED BY6=12

12=K