Question

A solid body weighing 25N is placed on a table. The area of contact is 50cm2. Find the pressure exerted by the solid on the table.
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Answer 1

Answer:

P= A/F= F/a^2

⟹P= 0.5×0.5 =25

⟹P=100Pa

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Answer 2

Given: A solid body weighing 25N is placed on a table. The area of contact is 50cm².

To find: The pressure exerted by the solid on the table.

Solution:

• Pressure exerted on a suface is the force applied per unit area of it.
• According to the formula of pressure,

        $P = \frac{F}{A}$

• P is the pressure exerted on the table, F is the forced exerted by the solid body and A is the area of the solid body.
• The area is given as 50 cm², but it shall be converted to its S.I. unit.

        $50 cm^{2} = \frac{50}{100^{2} } m^{2}$

                   $= 0.5 * 10^{-2}m^{2}$

• Calculating the pressure exerted on the table by the solid body,

        $P = \frac{25N}{0.5 * 10^{-2}m^{2} }$

            $= 5000 Pa$

Therefore, the pressure exerted by the solid on the table is 5000 pascals.