A solid cone of a base radius 10cm is cut into two parts through the midpoint of its height by a plane parllel to its base. find the ratio of the volume of the two parts of the cone
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Answer: 1/7
Step-by-step explanation:
△OAB∼△OCD (By AA similarity)
∴OBOA=CDAB⇒hh/2=10r⇒r=210=5cm
Given that cone cut into two parts through the mid point of its height H=2h
Volume of frustum of cone =3πH[R2+r2+Rr]
=3×2πh[102+52+10×5]=6175πh
Volume of cone OAB=31πr22h=31×π×52×2h=625πh
Required ratio = 25πh/6/175πh/6
= 1/7.
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