Question

in an ap the sum of first 11 terms is 44 and that of the next 11 terms is 55 find the ap​

Answer 1

Answer:

Step-by-step explanation:Let the AP be a, a+d, a+2d, ...; ==> First term is a and common difference is d  

ii) Sum of first 11 terms is: (11/2)*(2a + 10d) = 44  

This simplifies to: a + 5d = 4 - (1)  

iii) Sum of next 11 terms = 55; so sum of first 22 terms is 44 + 55 = 99.  

==> (22/2)(2a + 21d) = 99  

==> 2a + 21d = 9 -(2)  

iv) Solving (1) & (2), we have a = 39/11 and d = 1/11  

Hence, AP is; 39/11, 40/11, 41/11, 42/11, ..

hope it help u