Math, asked by VishalNath1793, 1 year ago

A solid consisting of right circular cone of height 120 cm and radius 60 cm standing on a hemisphere of radius 60 cm is placed upright in a right circular cylinder full of water such that it touches the bottom

Answers

Answered by ayushverma518
11

Step-by-step explanation:

We need to calculate the volume of the solid figure

The figure is made of two shapes:

Conical part

Hemispherical part

Step 1 : Calculate the volume of the conical part:

The following is the formula of calculating the volume of a cone:

        1/3 πr²H

Volume = 1/3 × 3.142 × 60 × 60 x 120

            = 452448 cm³

Step 2: Calculate the volume of the hemispherical part

Formula for calculating the volume of a hemisphere

       2/3πr³

Volume =    2/3 × 3.142 × 60 × 60 × 60

            =    452448 cm³

∴ The volume of the solid is:

     452448 + 452448 = 904896 cm³

Volume = 904896 cm³

Step 3: Find the volume of the cylinder:

Formula of calculating the volume of a cylinder

       πr²H

Volume = 3.142 × 60 × 60 × 180

            =  2036016 cm³

⇒The volume of the water remaining in the cylinder will the volume of the solid  subtracted from the volume of the cylinder.

2036016 cm³  - 904896 cm³   = 1131120 cm³

The volume of the water left is 1131120 cm³

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