Math, asked by raheenaebrahim123, 11 months ago

a solid consting of a cone standing on a hemisphere is imarsed in a cylinder of water as shown in fig find is left in the figure

Answers

Answered by kumarisangita
0

Answer:

solid consisting of a right cone standing on a hemisphere is placed upright in a right circular cylinder full of water and touches the bottom. Find the volume of water left in the cylinder, if the radius of the cylinder is 60cm60cm and its height is 180cm180cm, the radius of the hemisphere is 60cm60cm and height of the cone is 120cm120cm, assuming that the hemisphere and the cone have common base.

Asked on December 26, 2019 byavatar

Shagun Kurapati

ANSWER

For the cylinder we have

Radius of the base=r=60cm=r=60cm

Height =h=180cm=h=180cm

Volume of water that the cylinder contains =V=\pi { r }^{ 2 }h=\left\{ \pi \times { 60 }^{ 2 }\times 180 \right\} {cm}^{3}=V=πr

2

h={π×60

2

×180}cm

3

For conical part, we have

Radius of the base =r=60cm=r=60cm

Height ={h}_{1}=120cm=h

1

=120cm

Volume of conical part {V}_{1}=\cfrac { 1 }{ 3 } \pi { r }^{ 2 }{ h }_{ 1 }=\cfrac { 1 }{ 3 } \pi \times { 60 }^{ 2 }\times 120{ cm }^{ 3 }=\left\{\pi \times { 60 }^{ 2 }\times 40 \right\} { cm }^{ 3 }V

1

=

3

1

πr

2

h

1

=

3

1

π×60

2

×120cm

3

={π ×60

2

×40}cm

3

For hemispherical part, we have

Radius =r=60cm=r=60cm

Volume of the hemisphere { V }_{ 2 }=\left\{ \cfrac { 2 }{ 3 } \pi \times { 60 }^{ 3 } \right\} { cm }^{ 3 }\quad V

2

={

3

2

π×60

3

}cm

3

\Rightarrow { V }_{ 2 }=\left\{ 2\pi \times { 60 }^{ 2 }\times 20 \right\} { cm }^{ 3 }=\left( 40\pi \times { 60 }^{ 2 } \right) { cm }^{ 3 }\quad \quad ⇒V

2

={2π×60

2

×20}cm

3

=(40π×60

2

)cm

3

Hence volume of the water left out in the cylinder

\Rightarrow V={ V }_{ 1 }-{ V }_{ 2 }\quad =\left\{ \pi \times { 60 }^{ 2 }\times 180-\pi \times { 60 }^{ 2 }\times 40-40\pi \times { 60 }^{ 2 } \right\} { cm }^{ 3 }=\pi \times { 60 }^{ 2 }\times \left\{ 180-40-40 \right\} { cm }^{ 3 }⇒V=V

1

−V

2

={π×60

2

×180−π×60

2

×40−40π×60

2

}cm

3

=π×60

2

×{180−40−40}cm

3

=\cfrac { 22 }{ 7 } \times 3600\times 100{ cm }^{ 3 }=

7

22

×3600×100cm

3

=\cfrac { 22\times 36 }{ 700 } { m }^{ 3 }=

700

22×36

m

3

=1.1314{ m }^{ 3 }=1.1314m

3

solution

Answered on December 26, 2019 by

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Answered by omkar252627
0

in the cone and calender for hemisphere I have top on the way

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