If the HCF of 65 and 117 is expressible in the form 65m -117, find the value of m:
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Answer:
117= 65×1+52
65=52×1+13
Hcf = 13
but Hcf(65,117)= 65m-117
65m-117=13
65m= 117+13
m=130
2
m=2
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