A solid cube is cut in to two cuboids of equal volumes find the ratio of the total surface area of the given cube and that of one of the cuboid
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Here is ur answer ⤵️⤵️
Let the side of solid cube = a
TSA of cube = 6a²
When the cube is cut into two cuboid with equal volume, the cube will be cut into two equal halves through its side.
the cuboid thus formed will have dimension,
length (l)= a
breadth (b)= a
height (h)= a/2
TSA = 2 (lb + bh + lh)
= 2 (a² + a²/2 + a²/2)
= 2 (2a²)
= 4a²
Ratio = (TSA of cuboid) : (TSA of cube) = 4a² : 6a² = 2:3
The Ratio is 2:3.
Please mark this answer as brainliest ❤️☺️❤️
Here is ur answer ⤵️⤵️
Let the side of solid cube = a
TSA of cube = 6a²
When the cube is cut into two cuboid with equal volume, the cube will be cut into two equal halves through its side.
the cuboid thus formed will have dimension,
length (l)= a
breadth (b)= a
height (h)= a/2
TSA = 2 (lb + bh + lh)
= 2 (a² + a²/2 + a²/2)
= 2 (2a²)
= 4a²
Ratio = (TSA of cuboid) : (TSA of cube) = 4a² : 6a² = 2:3
The Ratio is 2:3.
Please mark this answer as brainliest ❤️☺️❤️
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