Question

A solid cube of dimensions 25cm×25cm×25cm and weighing 625 N is placed on a table .calculate the pressure exerted on the table.

Answer 1

Dimension =25cm×25cm×25cm. (a)

Weight =625N. (F)

We know,

$\large\green{\boxed{P=\dfrac{F}{A}}}$

where

• P is the pressure.
• A is the area of contact
• F is the force.

On substituting the values,

$\implies P= \dfrac{F}{A}$

$\implies P =\dfrac{625N}{a\times a}$

Since area = (side)$^{2}$

$\implies P =\dfrac{625N}{25cm\times 25cm}$

$\implies P=\dfrac{625N}{\dfrac{25m}{100}\times\dfrac{25m}{100}}$

$\implies P =\dfrac{625N\times 10000}{625m^{2}}$

$\implies P =\dfrac{\cancel{625N}\times 10000}{\cancel{625}m^{2}}$

$\implies P =10000N/m^{2}$

${\underline{\boxed{\red{.°. P =10^{4}Pa}}}}$

Therefore the pressure is 10000 Pa.

Answer 2

Answer:

= 25

= 25

= 25

= ×

= 25×25

= 625²

= 625 ×

100 × 100

= 625

10,000

= 625

10⁴

= 625 × 10`⁴ ²

= 625

Pressure = Force

area

= `625

`625 × 10`⁴

= 1

10`⁴

= 10⁴

= 10000 / ² 10⁴