Question

a solid cube of metal whose sides measure 2.2cm is melted to form a cylinderical wire of radius 1mm. find the length of the wire so obtained

Answer 1

3389.3 mm is the required length

Answer 2

Side of The Cube = 2.2cm
So, Vol. if The Cube
= (S)^3
= (2.2cm)^3
= 10.648 cubic cm....
*Radius = 1mm = 1/10cm
Now, Since the Cube is only melted to form the Cylinder.....
Therefore,
Vol. of the cube = Vol. of the cylinder
$= > 10.648 {cm}^{3} = \pi {r}^{2} h \\ = > 10.648 {cm}^{3} = \frac{22}{7} \times \frac{1}{10}cm \times \frac{1}{10} cm \times h \\ = > h = \frac{10.648 {cm}^{3} \times 10 \times 10 \times 7}{22 \times 1cm \times 1cm} \\ = > h = \frac{1064.8 {cm}^{3} \times 7}{22 {cm}^{2} } \\ = > h = 48.4cm \times 7 \\ = > h = 338.8cm$
HENCE, Length of the cylinder will be 338.8cm
THERE YOU GO!!!.....