A solid cuboid of iron with dimensions 53 cm × 40 cm × 15 cm is melted and recast into a cylindrical pipe. The outer and inner diameters of pipe are 8 cm and 7 cm respectively. Find the length of the pipe.
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volume of cubical iron =volume of cylindrical pipe
length x breadth x height =pi.{R^2-r^2} h
53 x 40 x 15 =22/7 x {4^2-(7/2)^2} h
53 x 40 x 15 =22/7 x 15/4 x h
h=2698.18 cm
hence length of cylindrical pipe =27m (approx)
length x breadth x height =pi.{R^2-r^2} h
53 x 40 x 15 =22/7 x {4^2-(7/2)^2} h
53 x 40 x 15 =22/7 x 15/4 x h
h=2698.18 cm
hence length of cylindrical pipe =27m (approx)
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LaughterqueenMaths AryaBhatta
Heya mate, Here is ur answer
Dimension of cuboid=53 cm× 40 cm × 15 cm
Volume of cuboid=lbh
=53×40×15
=31800 cm^3.
Let the height of the cylinder be h.
Outer Diameter=8
Outer Radius (r) =8/2
r=4 cm.
Inner Diameter=7 cm
Inner radius (r2)= 7/2 cm
=3.5 cm
Volume of hollow cylinder = π(r^2-r2^2)×h
When one solid is melted to form another, their volumes remain unchanged.
So,
Volume of cylinder= volume of cuboid
h=2698.18 (approx)
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