A solid cylinder has mass M, length L and radius R. The moment of inertia of this cylinder about generator axis will be-
Answers
Answered by
4
The moment of inertia will be L = √3R
Explanation:
The moment of inertia of solid cylinder about its axis is given by:
I = ½ MR^2 ……….. (i)
The moment of inertia perpendicular to the length is given by:
I = M (L^2/12 + R^2/4) ……….. (ii)
Comparing equation (i) and (ii)
½ MR^2 = M (L^2/12 + R^2/4)
Solving for L,
L = √3R
Answered by
10
Answer: M.I = 3MR²/2
Explanation: please read the photo
Hope this will help you
Thanks
Attachments:
Similar questions