A Solid Cylinder has total surface area of 462cm^2.Its curved surface area is one-third of its total surface area.Find the radius and height of the cylinder ?
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Given that, total surface area if cylinder is 462 cm².
Also given that, it's curved surface area is one-third of its total surface area.
Curved surface area = (Total surface area)/3
⇒ C.S.A. = 462/3
⇒ C.S.A. = 154 cm²
Now,
Curved surface area = 154 cm² = 2πrh
Total surface area = 462 cm² = 2πr(r + h)
Divide C.S.A. by T.S.A.
⇒ (2πrh)/[2πr(r+h) = 154/462
⇒ h/(r + h) = 1/3
Cross-multiply them
⇒ 3h = r + h
⇒ 2h = r
⇒ h = r/2
Now, Area of two circles = 462 - 154 = 308 cm²
Area of two circles = 2πr² = 308
⇒ 2πr² = 308
⇒ 2 × 22/7 × r² = 308
On solving we get,
⇒ r = 7 cm
So,
⇒ h = 7/2 cm = 3.5 cm
Therefore,
Radius of the cylinder is 7 cm and height is 3.5 cm.
Mankuthemonkey01:
good one
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20
☆GIVEN☆
- T.S.A OF CYLINDER=462cm²
- C.S.A OF CYLINDER=1/3 OF T.S.A
☆FIND☆
- RADIUS AND HEIGHT OF CYLINDER☆
☆According to the above information☆
- C.S.A=1/3*462
- C.S.A=154cm²
☆NOW, APPLYING FORMULA HERE☆
- CAS+2πr²=TSA
- 154+2πr²=462
- 2πr²=462-154
- πr²=308/2
- 22/7*r²=154
- r²=√49
- r=7cm
☆TO FIND HEIGHT APPLY THE FORMULA OF CSA☆
- CSA=2πrh
- 154=2*22/7*7*h
- h=7/2
- h=3.5cm
☆HENCE☆
- RADIUS=7cm
- HEIGHT=3.5cm
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