Question

A solid cylinder of mass 20 kg rotates about its axis with angular speed 100 radian per second

Answer 1

Given,

Mass of cylinder (M) = 20 Kg

Radius of its ( R) = 0.25 m

Angular speed (w ) = 100 rad/s

We know, moment of inertia of solid cylinder ( I) = (1/2)MR²

= (1/2) × 20× (0.25)²

= 0.625 kg.m²

Kinetic energy associated with the rotation of the cylinder is given by

K.E = (1/2)Iw²

= (1/2) × 0.625 × (100)²

= 3125 joule

angular momentum = Iw = 0.625* 100 = 62.5 js