A solid cylinder of mass 50 kg and radius 0.5 m
is free to rotate about the horizontal axis. A massless string
is wound round the cylinder with one end attached to it
and other hanging freely. Tension in the string required to
produce an angular acceleration of 2 revolutions s⁻² is :
(a) 25 N (b) 50 N [2014]
(c) 78.5 N (d) 157 N
Answers
Answered by
3
Answer:
c) 78.5
follow me.......
Answered by
8
Answer:
D) 157 N
Explanation:
Mass of the cylinder m=50kg (Given)
Radius of the cylinder r =0.5m (Given)
α = 2 rev/s²
Torque by Tension in string = T × R= T × 0.5 = T/2 N-M
= T = Iα = T/2 = Iα
= T/2 = 50 × (0.5)² × 4π/2
T = 157N
Therefore, Tension in the string required to produce an angular acceleration of 2 revolutions s⁻² is 157N.
pls mark as brainliest answer
Similar questions