Question

A solid cylindrical steel column is 4.0cm long and 9.0cm in diameter. What will be its decrease in length when carrying a load of 80000kg. Young modulus = 1.9×10^11Pa​

Answer 1

Answer:

correct Answer is : decrease in length when carrying a load of 80000kg is ≈2.6 mm

Explanation:

According to definition of stress , it is given as load per unit cross section

Strain = stress/ Young's Modulus.

Y=F/ A / ΔL/L

ΔL=FL/AY

area of cross section = π r² = π(0.045)²= 6.36 x 10⁻³ m²

= ( 8 x 10 ⁴) x 9.8 x 4 / 6.36 x 10 ⁻³ x 1.9 x10 ¹¹

=0.00259m

=2.59mm

≈2.6 mm