A solid density 5000 kg meter cube weighs 0.5kg in air it is completely immersed in a liquid of density 8000kg meter cube calculate apparent weight of the solid in the liquid
Answers
Answered by
3
Density ρ = 5000 kg/m³ Weight = 0.5 kg f in air
mass M = 0.5 kg
Volume V = M / ρ = 0.5 / 5000 = 10⁻⁴ m³
mass of water displaced = V * density of water
= 10⁻⁴ * 1000 = 0.1 kg
Apparent weight = wt in air - wt of water displaced
= 0.5 kg f - 0.1 kg f
= 0.4 kg f
mass M = 0.5 kg
Volume V = M / ρ = 0.5 / 5000 = 10⁻⁴ m³
mass of water displaced = V * density of water
= 10⁻⁴ * 1000 = 0.1 kg
Apparent weight = wt in air - wt of water displaced
= 0.5 kg f - 0.1 kg f
= 0.4 kg f
Similar questions