Physics, asked by PhysicsHelper, 1 year ago

A solid floats in a liquid in a partially dipped position.
(a) The solid exerts a force equal to its weight on the liquid.
(b) The liquid exerts a force of buoyancy on the solid which is equal to the weight of the solid.
(c) The weight of the displaced liquid equals the weight of the solid.
(d) The weight of the dipped part of the solid is equal to the weight of the displaced liquid.

Answers

Answered by shashwat1564
2

I think option b is correct

Answered by tiwaavi
12

Answer ⇒ Option (a)., (b)., and Option (c).

Explanation ⇒ When the solid is dipped in water, then it always exerts and force equal to its weight on it. Infact everything of this universe when fall in something exerts an force equal to its weight. Thus, Option (a). is correct.

According to the Archimedes principle, there will be force given by the liquid to solid, which is called as upthrust, which will be equal to weight of the solid. Thus, Option (b). is correct.

When we dip some solid in water, then weight of the solid will be the weight of the liquid displaced. It is the statement of Floatation law. Hence, Option (c). is correct.

By the law of flotation, Option (c). is correct. Now, If you read option (d). you will find that both are opp. If option (c). is true, then (d). can't be true. And It is sure, that option (c). is true. Thus, option (d). is incorrect.

Hope it helps.

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