a solid floats with 1/4 of its volume above the surface of water calculate the density of the solid
Answers
Answered by
2
the density of solid that floats 1/4 of its volume
= actually floatation depends on two factor
1.weight of liquid diplaced
2. density
but this solid you stated in floatation !!
this implies that density of solid =water density
density of solid=1g/cm^3
if you stated 1/4 ....it may be affected by weight of liquid diplaced !
hope this helps you !!!
= actually floatation depends on two factor
1.weight of liquid diplaced
2. density
but this solid you stated in floatation !!
this implies that density of solid =water density
density of solid=1g/cm^3
if you stated 1/4 ....it may be affected by weight of liquid diplaced !
hope this helps you !!!
Answered by
7
Volume of solid = V
Volume of water displaced = 3V/4
Weight of solid = Buoyant Force
mg = F
Vd’g = (3V/4)dg
d’ = 3d/4
d’ = (3 × 1 g/cm³) / 4
d’ = 0.75 g/cm³
Density of solid is 0.75 g/cm³
Similar questions