Question

At present abi is twice as old as reeta. after seven years their age difference is 5 years. the present age of reeta is

Answer 1

Reeta's present age=x years
Abi's present age= 2x years
after 7 years their present age
Reeta's age= x+7
and Abi's age= 2x+7
A/Q
age difference= 5
=>2x+7-(x+7)=5
=>x=5

Answer 2

Concept Introduction:

If the sum of ages is $X$ and $Y$ and the ratio of their ages is $p:q$ respectively, then you can determine the age of $Y$ by using the formula shown below: Age of $Y$ = Ratio of $Y$/ Sum of ratios $x$ sum of ages. Age of $Y = q/ (p+q) x A$.

Given:

At present abi is twice as old as reeta. After seven years their age difference is $5$ years.

To Find:

We have to find the present age of reeta.

Solution:

Reeta's present age=$x$ years

Abi's present age= $2x$ years

after $7$ years their present age

Reeta's age= $x+7$

and Abi's age=$2x+7$

$A/Q$

age difference= $5$

=>$2x+7-(x+7)=5$

=>$x=5$

Final Answer:

the present age of reeta is $5$ years.

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