Question

A solid floats with 1/5th of its volume above water. Find density of the solid.​

Answer 1

Answer:

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Let V be the volume and d be the density of the solid then weight of the body =Vdg.

Volume of solid body inside water =V−

4V= 43VWeight of water displaced by immersed portion of the body

= 43V×10 3×g∴ By the principle of floatation,Vdg= 43V ×10 3g⇒d= 43×10 3 =750kgm −3 .