Question

Two bodies of masses 6kg and 4kg are connected to a string
passing over a light frictionless pulley, then find the thrust on the
pulley. g = 10 m/s2​

Answer 1

Answer:

Since 6kg is heavier than 4 kg so it will accelerate down while 4 kg will accelerate up

So the equation of net force on 6kg is given as

6×10−T=6a

equation of net force on 4kg is given as

T−4×10=4a

now add the above two equations

6×10−(4×10)=(6+4)×a

60  - 40 = 10a

a = 2m/s  

2

 

So 6 kg will accelerate downwards while 4 kg will accelerate upwards  

with acceleration 2 m/s  

2

 

now in order to find the tension force

T−4×10=4×2

T = 48N

So the tension in the string is 48 N

Explanation:

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