A solid iron cuboid is kept on a table top. The mass of cuboid is 6 kg and its dimensions are 30cm *15cm*10cm . force and pressure exerted by the cuboid on table top if it made to lie on the table top with its side dimensions 30m*15cm are
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The force exerted by the cubiod on table top will be 58.8 N while the pressure exerted will be 1.307 kPa.
• This follows from fundamental laws of physics where we have force equals to mass times acceleration.
• Here, acceleration is due to gravity,
• So F = m * g
• 6 kg * 9.8 m/s^2
• 58.8 N
•Next up, we have Pressure is the Force exerted per unit area.
•So , P = F/A
• 58.8 N/ (.3 * .15)m^2
• 1306.66667
• 1307 Pa = 1.307 kPa
•for all the above formulas we should use SI units,
•Pa stands for Pascal,
•N stands for Newton.
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