A solid iron pole consists of a cylinder of height 220 cm and the base diameter 28cm which is surmounted by another cylinder of height 60cm and radius 8cm Find the mass of the pole given that 1 cm cube of iron has approximately 8g mass (use pie=3.14)
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so we first find valume of first cylinder
v=πr²h
=3.14×196×220
=135396.8 cm³
so find valume of second cylinder
v=πr²h
=3.14×64×60
= 12057.6cm³
so the valume of total pole is
=135396.8cm³+12057.6cm³
=1474544.4 cm³
so the mass of pole
=8×147454.4
=1179635.2 g
=1179635.2/1000 kg
=1179.6 kg
so the mass of pole is 1179.6 kg
v=πr²h
=3.14×196×220
=135396.8 cm³
so find valume of second cylinder
v=πr²h
=3.14×64×60
= 12057.6cm³
so the valume of total pole is
=135396.8cm³+12057.6cm³
=1474544.4 cm³
so the mass of pole
=8×147454.4
=1179635.2 g
=1179635.2/1000 kg
=1179.6 kg
so the mass of pole is 1179.6 kg
wrong answer
what is the exact answer
892.26kg
if u had given that daimeter 24cm answer would be 892.26 kg
so the answer is 1179.6kg
u had given that daimeter is 28cm
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