A solid is composed of a cylinder with hemispherical ends. If the
whole length of the solid is 105 cm and the radius of each of the
hemispherical ends is 17.5 cm, find the cost of polishing its surface at
the rate of ₹5 per dm².
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Radius of each hemispherical end = 7 cm
Height of each hemispherical part
its radius = 7 cm
Height of the cylindrical part
=(104−2×7)cm=90cm
Area of surface to be polished = 2 (curved surface area of the hemisphere)+( curved suface area of the cylinder )
= [ 2 [ 2 πr2) +2πrh] sq units
=[(4×227×7×7)+(2×227×7×90)]cm2
=(616+3960)cm2=4576cm2
=(457610×10)dm2= 45.76 dm2 [∵ 10 cm = 1 dm].
∴ cost of polishing the surface of the solid
=₹(45.76×10)=₹457.60
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