A solid is composed of a cylinder with hemispherical ends.if the
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diameter of each hemispherical ends of the solid = 28 cm
radius = 28 ÷ 2 = 14 cm
height of the cylinderical portion of solid
h = whole length of solid - 2 × radius of each hemisphere
h = 98 - 2 × 14 = 98 - 28 = 70 cm
c.s.a of cylinder = 2πrh
= (2 × 22 × 14 × 70) / 7 = 6160 cm^2
c.s.a of 2 hemisphere = 2 × ( 2πr^2)
= 2 × ( 2 × 22 × (14)^2)/ 7
= 2464 cm^2
c.s.a of solid = 6160 + 2464
= 8624cm^2
cost of 1 cm^2 = 15 paise = Rs 0.15
cost of polishing the surface of the solid
= 0.15 × 8624 = Rs 1293.60
Answer: required cost = Rs 1293.60
radius = 28 ÷ 2 = 14 cm
height of the cylinderical portion of solid
h = whole length of solid - 2 × radius of each hemisphere
h = 98 - 2 × 14 = 98 - 28 = 70 cm
c.s.a of cylinder = 2πrh
= (2 × 22 × 14 × 70) / 7 = 6160 cm^2
c.s.a of 2 hemisphere = 2 × ( 2πr^2)
= 2 × ( 2 × 22 × (14)^2)/ 7
= 2464 cm^2
c.s.a of solid = 6160 + 2464
= 8624cm^2
cost of 1 cm^2 = 15 paise = Rs 0.15
cost of polishing the surface of the solid
= 0.15 × 8624 = Rs 1293.60
Answer: required cost = Rs 1293.60
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