a solid is in the form of a right circular cylinder with hemispherical on both the ends. the total height of the solid is 30 cm and the diameter of the cylinder is 10 cm. the radius of the hemispherical part is the same as of the cylindrical part. find the total surface area of the solid.
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A solid is in the form of a right circular cylinder with hemispherical on both the ends. the total height of the solid is 30 cm and the diameter of the cylinder is 10 cm. the radius of the hemispherical part is the same as of the cylindrical part. find the total surface area of the solid.
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Total height= 30cm
height of cylinder=13cm
height of cone=30-18 (radius of hemisphere=height)
therefore height of cone= 12cm
C.S.A. of hemisphere:
2*22/7*5^2
=157.14 cm^2
C.S.A. of cylinder:
2*22/7*5*13
=408.571 cm^2
C.S.A of cone :
22/7*5*13
=204.28
Adding all C.S.As we get
408.57
204.28
+157.14
=769.99m^2 [Ans. =Surface area of toy]
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