Math, asked by kingitaat, 1 year ago

a solid is in the form of a right circular cylinder with hemispherical on both the ends. the total height of the solid is 30 cm and the diameter of the cylinder is 10 cm. the radius of the hemispherical part is the same as of the cylindrical part. find the total surface area of the solid.

Answers

Answered by pawansingh777p
0

Answer:

Step-by-step explanation:

A solid is in the form of a right circular cylinder with hemispherical on both the ends. the total height of the solid is 30 cm and the diameter of the cylinder is 10 cm. the radius of the hemispherical part is the same as of the cylindrical part. find the total surface area of the solid.

Ask for details FollowReport by Kingitaat 24 hours ago

Answered by Diya999
1

Total height= 30cm

height of cylinder=13cm

height of cone=30-18 (radius of hemisphere=height)

therefore height of cone= 12cm

C.S.A. of hemisphere:

2*22/7*5^2

=157.14 cm^2

C.S.A. of cylinder:

2*22/7*5*13

=408.571 cm^2

C.S.A of cone :

22/7*5*13

=204.28

Adding all C.S.As we get

  408.57

  204.28

+157.14

=769.99m^2 [Ans. =Surface area of toy]

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