Question

A solid is in the form of a right circular cylinder with a hemisphere one end and a cone at the other end. The radius of the common base is 8 cm. and the heights of the cylindrical and conical portion are 10 cm and 6 cm respectively. Find the total surface area of the solid.
(use π = 3.14)

Answer 1

Answer:

Total Surface Area of Solid = C.s.a of hemisphere+C.s.a of cone+C.s.a of Cylinder

slant height of cone=√h²+r²

=√6²+8²

=√100

=10cm

height of cone = 10 cm

radius of hemisphere =radius of cone=radius of cylinder=8cm

T.S.A of solid=2πrh+2πr²+πrl

=πr[2h+2r+l]

=3.14*8[2*10+2*8+10]

=25.12[36+10]

=25.12*46

=1155.52 cm²

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Answer 2

Answer:

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