Question

A solid is in the form of cylinder with hemispherical ends. The total hight of the solid is 19cm and diameter of the cylindrical and hemispherical part is 7cm. Find the total surface area of the solid.​

Answer 1

$\huge\underline\bold\blue{AnsWer}$

$\bf{\underline\green{Given:-}}$

• Total height of solid = 19 cm
• Diameter of the cylindrical and hemispherical part = 7cm

$\bf{\underline\green{Find:-}}$

Find total surface area of the solid.

$\large\underline\bold\blue{SoluTion}$

• Height of cylinder = 5cm
• Height of hemisphere = 7cm
• Radius of hemisphere = 7cm

TSA of solid = CSA of cylinder + CSA of sphere

=$2πrh + 2πr^2$

=$2π ( rh + r^2 )$

=2 × $\frac{22}{7} ( 7 × 5 + 49 )$

= $\frac{44}{7}( 35 + 49 )$

= $\frac{44}{7} × 84$

= $44 × 12$

= $528 \:sq \:cm.$