A solid is in the form of right circular cone mounted on a hemisphere the radius of the hemisphere is 2.1 cm and the height of the cone is 4 cm the solid is placed in a cylindrical tub full of water in such a way that the holes for leaders summit in water if the radius of the cylinder is 5 cm and the height is 9.8 cm find the volume of the water left in the dub
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Volume of water left =volume of cylinder - (volume of cone + volume of hemisphere)
= 770-(8.8+29.404)
= 770-38.204
= 731.796 CC
OR
Volume of water left=volume of cylinder-(vol of cone+ vol of hemisphere).
22/7×5×5×9.8-(1/3×22/7×2.1×2.1×4 +2/3×22/7×2.1×2.1×2.2)
=732.116
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