Question

A solid metal cone with radius of base 12 cm and height 24 cm is melted to form solid spherical balls of diameter 6 cm each find the number of balls does formed

Answer 1

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$Radius \: of \: cone = 12cm \\ Height \: of \: \: cone \: = 24cm \\ \\ Now, \: Volume \: of \: cone \: = \frac{1}{3} \pi \: r {}^{2} h \\ \\ = > \frac{1}{3} \times \frac{22}{7} \times (12) { }^{2} \times 24 \\ \\ = > \frac{22 \times 144 \times 24}{21} \\ \\ = > \frac{76032}{21} \\ \\ = > \frac{25344}{7} cm {}^{3} \\ \\ Diameter \: of \: ball \: = 6cm \\ Radius \: of \: each \: ball \: = 3cm \\ \\ \\ Now, \: Volume \: of \: each \: ball = \frac{4}{3} \pi \: r {}^{3} \\ \\ = > \frac{4}{3} \times \frac{22}{7} \times 27 \\ \\ = > \frac{2376}{21} \\ \\ = > \frac{792}{7} cm {}^{3} \\ \\ Total \: No.of \: balls \: formed \: by \: melting \: the \: cone \\ n = \frac{volume \: of \: cone}{volume \: of \: ball} \\ \\ n = \frac{25344}{7} \times \frac{7}{792} \\ \\ = > n = \frac{25344}{792} \\ \\ = > n = 32$

So, 32 balls formed by melting a cone✔✔
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Answer 2

Answer:

Step-by-step explanation:

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