Question

a solid metal shaft od diameter 50 mm and length 2m is twisted in a testing machine until one end rotates through an angle of 5 degree with respect to the other end. For this twist , torque is 70 Nm.Calulate max shear stress

Answer 1

Answer:

The new acceleration is 12 m/s²

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➤ How to solve ?

A Force is a push / pull upon an object resulting from the people interaction with any of the another object.

Newton's 2nd law stated as F = Ma

Means,

•F acting on an object is equal

⠀⠀⠀⠀⠀to the mass of an object time it's A.

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➤ Solution :

As , F = ma

➨ a = F / m

➨ 2 = F / m

Now , we want to see the value of a produced with 3f respectively

➨ a = F / m

➨ a = F / m/ ²

➨ a = 6 F / m

As we have already got F / m = 2

➨ 1 / 6 a = 2

➨ a = 12 m/s ²

⁖ New Acceleration is 12 m/s ²

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