Math, asked by Prashant9763, 1 year ago

A solid metallic cuboid of dimensions 9 m x 8 m x 2 m is melted and recast into solid cubes of edge 2 m. Find the number of cubes so formed.

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Answered by Anonymous

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Answered by BrainlyMOSAD

hey mate !!

here is your answer !!

Answer

18

in the questions GIVEN ,

length of cuboid = 9m

Breadth of the cuboid = 8m

height of the cuboid = 2m

volume of the cuboid = l × b × h

9m × 8m × 2m

72m2 × 2m

144m3

Again we find volumes of the cube .

here side of cube = 2

using formula,

volume of cube = (side)3
$v \: of \: cube \: = {2}^{3} \\ \\ = 8 {m}^{3}$
$no \: of \: cubes \: form \: = \frac{vol \: of \: cuboid }{volume \: of \: cube} \\ \\ no \: of \: cube \: form \: = \frac{144}{8} \\ \\ = 18$

therefore the number of cube formed is equal to 18 .

be brainly

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