Math, asked by maheshhugar19, 3 days ago

A solid metallic sphere of diameter 21 cm is melted and recast into a number of smaller cones, each of diameter 7cm and height 3 cm. Find the number of cones so formed

Answers

Answered by Anonymous
0

Answer:

 \huge \sf \orange { \star} \sf \pink{ \mathfrak{Solution }}

Diameter of sphere =21 cm

 \tt \: Radius = \frac{21}{2} cm \\

Height of the cone =3cm

 \tt \: Radius  \: of  \: the  \: cone  =  \frac{7}{2} cm

 \tt \: Volume  \: of \:  the \:  sphere  =  \frac{4}{3} \pi {r}^{3}

 \tt \:  =   \frac{4}{3} \pi \times (  {\frac{21}{2} })^{3} \:  {cm}^{3}   \\

Let n be the number of cone formed,

then,

n = (volume of the sphere)/(volume of cone)

 \tt \: n =  \frac{( \frac{4}{3}  \times \pi \times  ({ \frac{21}{2} })^{3} }{ \frac{1}{3} \times \pi \times  ({ \frac{7}{2} })^{2}  \times 3 }   \\

 \tt \green{∴ \: n \:  =  \: 378}

Number of cones formed = 378

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