A solid metallic sphere of diameter 28 cm is melted and recast into a number of smaller cones, each of diameter tex]4\frac{2}{3}[/tex] cm and height 3 cm. Find the number of cones so formed.
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Answer:
Number of Smaller cones formed is 672.
Step-by-step explanation:
SOLUTION:
Given :
Diameter of a solid metallic sphere = 28 cm
Radius of solid metallic sphere, R = 28/2 = 14 cm
Diameter of a Smaller cone = 14/3 cm
Radius of a circular cone , r = ½ × 14/3 = 7/3 cm
Height of a Smaller cone ,h = 3 cm
Here, a solid metallic sphere is melted and recast into a smaller circular cones.
Number of Smaller cones,n = Volume of solid metallic sphere / Volume of cone
n = 4/3 πR³ / ⅓ πr²h
n = 4R³ / r²h
n = 4 × 14³ / (7/3)² × 3
n = (4 × 14 × 14 × 14)/ (49/9 × 3)
n = (4 × 14 × 14 × 14)/ (49/3)
n = (4 × 14 × 14 × 14) × 3/49
n = 672
Hence, number of Smaller cones formed is 672.
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