A solid object weighing 5kg in air, weighs 4kg in kerosene Find ...it's volume and it's density.
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actual weight= W= 5kg
apparent weight= W'= 4 kg
volume= V
density= d
density of kerosene= 820
buoyancy = W- W'
= 1kg
Buoyancy = density of kerosene x volume x g
V'= 1.219 x 10 ⁻³
as the body is completely immersed,so V= V'
now W= 5
Vpg= 5
p = 4100 kg/m3
apparent weight= W'= 4 kg
volume= V
density= d
density of kerosene= 820
buoyancy = W- W'
= 1kg
Buoyancy = density of kerosene x volume x g
V'= 1.219 x 10 ⁻³
as the body is completely immersed,so V= V'
now W= 5
Vpg= 5
p = 4100 kg/m3
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