Question

A solid of density 5,000 kg/m³ weighs 0.5kg in air.It is completely immersed in a liquid of density 800 kg/m³. calculate the apparent weight of the solid in the liquid​

Answer 1

Answer:

Density ρ = 5000 kg/m

3

Weight = 0.5 kg f in air

mass M = 0.5 kg

Volume V = M / ρ

= 0.5 / 5000 = 10

−4

m

3

mass of water displaced = V

∗

density of water

= 10

−4

∗1000 = 0.1 kg

Apparent weight = wt in air - wt of water displaced

= 0.5 kg f - 0.1 kg f

= 0.4 kg f