Question

A solid of density 5000(kg)/(m^3) weghs 0.5 kg f in air. It is completely immersed in water of density 1000(kg)/(m^3). (a) Calculate the apparent weight of the solid in water. (b) what will be its apparent weight if water is replaced by a liquid of density 8000 (kg)/(m^3)?

Answer 1

Answer:

Density ρ = 5000 kg/m

3

Weight = 0.5 kg f in air

mass M = 0.5 kg

Volume V = M / ρ

= 0.5 / 5000 = 10

−4

m

3

mass of water displaced = V

∗

density of water

= 10

−4

∗1000 = 0.1 kg

Apparent weight = wt in air - wt of water displaced

= 0.5 kg f - 0.1 kg f

= 0.4 kg f