A solid of density 5000(kg)/(m^3) weghs 0.5 kg f in air. It is completely immersed in water of density 1000(kg)/(m^3). (a) Calculate the apparent weight of the solid in water. (b) what will be its apparent weight if water is replaced by a liquid of density 8000 (kg)/(m^3)?
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Answer:
Density ρ = 5000 kg/m
3
Weight = 0.5 kg f in air
mass M = 0.5 kg
Volume V = M / ρ
= 0.5 / 5000 = 10
−4
m
3
mass of water displaced = V
∗
density of water
= 10
−4
∗1000 = 0.1 kg
Apparent weight = wt in air - wt of water displaced
= 0.5 kg f - 0.1 kg f
= 0.4 kg f
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