A solid of density 'd' has weight 'w'. It is completely immersed in a liquid of density 'd', then apparent weight of the solid is :
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Answer:
Explanation:
→ Apparent weight of the solid = (Weight of solid in air) - (loss of weight of solid in liquid)
→ but, loss of weight of solid in liquid is equals to the weight of liquid displaced.
→ Thus, weight of liquid displaced is the product of Volume of solid and density of liquid.
∴ Volume of solid = W/D
where,
weight of solid = W
density = D
but, density of liquid = d.
→ Thus, weight of liquid displaced = w.d / D = Loss of weight of solid into liquid.
∴ Apparent weight = W - W.d / D
= W (1 - d/D)
→ Hence, apparent weight of the solid is W (1 - d/D).
Explanation:
1
Secondary School Physics 13 points
A solid of density 'd' has weight 'w'. It is completely immersed in a liquid of density 'd', then apparent weight of the solid is :
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Answer:
Explanation:
→ Apparent weight of the solid = (Weight of solid in air) - (loss of weight of solid in liquid)
→ but, loss of weight of solid in liquid is equals to the weight of liquid displaced.
→ Thus, weight of liquid displaced is the product of Volume of solid and density of liquid.
∴ Volume of solid = W/D
where,
weight of solid = W
density = D
but, density of liquid = d.
→ Thus, weight of liquid displaced = w.d / D = Loss of weight of solid into liquid.
∴ Apparent weight = W - W.d / D
= W (1 - d/D)
→ Hence, apparent weight of the solid is W (1 - d/D).