Question

a solid rectangular block of dimension 4.4m,2.6m and 1m is cast in a hollow cylinderical pipe of internal radius 30cm and thickness 5cm.Find the length of the pipe

Answer 1

let length of pipe be l cm.
then
volume of block=(4.4*2.6*1)m³
=(440*260*100)m³
r=internal radius=30cm and
R=external radius=30+5=35cm
volume of iron in pipe=
=external vol.-internal vol.
=π(R²-r²)h=π(R+r)(R-r)h
π*65*5*h


now,
vol. of iron in the pipe=vol. of iron in the block
π*65*5*h=440*260*100
h=11200cm=112m
length of the pipe is 112m

Answer 2

u xan solve it ba this way