A solid right circular cone is cut into two parts at middle of it's height by a plane parallel to it's base. Find the ratio of the volume of the smaller cone to the whole cone
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Let the height and the radius of whole cone be H and R respectively.
The cone is divided into two parts by drawing a plane through the mid point of its height and parallel to the base.
Let the radius of the smaller cone be r cm.
In ∆OCD and ∆OAB,
∠OCD = ∠OAB (90°)
∠COD = ∠AOB (Common)
∴∆OCD ∼ ∆OAB (AA Similarity criterion)
⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️ now see picture
Thus, the ratio of smaller cone to whole cone is 1 : 8.
The cone is divided into two parts by drawing a plane through the mid point of its height and parallel to the base.
Let the radius of the smaller cone be r cm.
In ∆OCD and ∆OAB,
∠OCD = ∠OAB (90°)
∠COD = ∠AOB (Common)
∴∆OCD ∼ ∆OAB (AA Similarity criterion)
⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️ now see picture
Thus, the ratio of smaller cone to whole cone is 1 : 8.
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Let the height and the radius of whole cone be H and R respectively.
The cone is divided into two parts by drawing a plane through the mid point of its height and parallel to the base.
Let the radius of the smaller cone be r cm.
In ∆OCD and ∆OAB,
∠OCD = ∠OAB (90°)
∠COD = ∠AOB (Common)
∴∆OCD ∼ ∆OAB (AA Similarity criterion)
Thus, the ratio of smaller cone to whole cone is 1 : 8
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